The Missing Map · Chapter 1 continued

Behind the cabinet

Pieces become a whole. A flat record becomes a solid clue.

The evidence so far

The old plan shows a 12 m² back room; the current survey marks that corner as inaccessible. Behind a loose board, the group found sketches pointing to a cabinet. Their calculations have checked the records, but nobody has yet seen what is behind the wall.

Two lessons, each planned for approximately 50 minutes. Use graph paper for work. Responses are not saved or submitted.

Lesson 1.4 · The Cabinet’s Outline

One outline. More than one method.

The cabinet stood beside the back wall. Tess stopped Mara before she tried to pull it forward.

“We’re taking inventory. We’re not moving furniture by ourselves.”

They asked Ada, the town’s workshop caretaker, for help. While she checked the cabinet, Jun spotted a paper template sticking out of its drawer.

“A replacement top,” he said. “Look at the corner cuts. We could measure the whole rectangle and take them away.”

Mara studied it. “Or split what’s left into shapes we already know.”

“Both,” Eli said. “If we’re describing the same surface, the answers should agree.”

Get Started · 5 minutes

Find the area of a triangle with base 10 cm and perpendicular height 8 cm. Then find a parallelogram with the same base and height. Explain the relationship.

Investigate · 18 minutes

The cabinet-top template fits in a 10 dm × 6 dm rectangle. Each upper corner cut is a right triangle with horizontal leg 2 dm and vertical leg 3 dm. The diagram uses one consistent scale.

10 dm6 dm2 dm2 dm3 dm3 dm
  1. Sketch the template. Find its area by subtracting the corner triangles from the enclosing rectangle.
  2. Find its area by adding non-overlapping pieces. Mark the dimensions you use.
  3. Explain why the two methods agree. What would go wrong if you subtracted 2 × 3 for each corner?
  4. A carpenter has 54 dm² of material. Is that enough for the top’s area? Does that alone establish that the template will fit the material?
HintEach missing triangle is half a 2 dm × 3 dm rectangle. For addition, the bottom rectangle has height 3 dm. The upper region can be split into a central rectangle and two triangles.

Make Sense and Practice · 20 minutes

A composite polygon can be measured by adding non-overlapping areas or subtracting excluded areas. Account for every piece exactly once. Area alone does not determine shape or whether one shape fits inside another.

Worked example: an 8 cm × 5 cm rectangle with one right-triangle corner removed (legs 2 cm and 4 cm) has area 40 − ½ × 2 × 4 = 36 cm².

  1. A 12 cm × 8 cm rectangle has two triangular corners removed. Each has legs 3 cm and 4 cm. Find the remaining area.
  2. A shape consists of a 7 m × 4 m rectangle and a triangle attached along the 7 m side with perpendicular height 2 m. Find the total area.
  3. A 9 cm × 6 cm rectangle has a right-triangle corner removed with legs 2 cm and 3 cm. A student reports 48 cm². Identify and correct the error.
  4. Draw a composite polygon with area 30 square units. Show two ways to find its area.
Check your practice

1. 84 cm². 2. 35 m². 3. The student subtracted the full 2 × 3 rectangle rather than half; correct area 51 cm². 4. Answers vary; an example is a 6 × 6 square with a 2 × 3 rectangular corner removed.

Close the case · 7 minutes

Write a short recommendation: what area should Ada record for the cabinet top, and what else must a carpenter check before cutting?

After you have explained

The area is 54 dm²: 60 − 3 − 3. Addition gives 30 + 18 + 3 + 3. The carpenter must also check the stock’s shape and dimensions, orientation, and cutting allowance.

Ada unlocked the drawer. Beneath the template was a small wooden box and a folded cutting pattern.

“The top measures fifty-four square decimeters,” Jun said. “But that doesn’t mean any fifty-four-square-decimeter board will fit.”

Ada smiled. “Keep that distinction. You’ll need it.”

Lesson 1.5 · A Box of Records

From flat pattern to solid object.

The cutting pattern showed six rectangles. Eli compared it with the box.

“Six faces,” he said. “We should be able to match them.”

Mara added the three measurements written along the edge. Tess shook her head.

“That gives a length. We’re trying to cover a surface.”

Mara crossed out her sum. “Then let’s count the faces, not just the edges.”

Get Started · 5 minutes

A rectangle measures 5 cm × 3 cm. Find its area and perimeter. Explain why the units differ.

Investigate · 18 minutes

The closed rectangular box has length 6 cm, width 4 cm, and height 3 cm. This net has four faces in a strip, with the top and bottom attached. Each label gives that face’s dimensions.

4 × 36 × 34 × 36 × 36 × 46 × 4

All face dimensions are in centimeters. Matching colors mark equal-area face pairs; labels also identify each pair.

  1. List all six face areas and find the total exterior surface area.
  2. Explain why there are two faces of each size.
  3. Sketch the net on graph paper. Label matching edges. How will it fold?
  4. Suppose the lid is omitted. Which area disappears? Find the open box’s exterior surface area, excluding material thickness.

HintOrganize the faces into three pairs: two 6 × 4 faces, two 6 × 3 faces, and two 4 × 3 faces. Add areas, not edge lengths.

Make Sense and Practice · 20 minutes

A net is a flat arrangement of faces that can fold into a solid. Surface area is the total area of its exterior faces. For a closed rectangular prism, add two copies of length × width, length × height, and width × height. Surface area is in square units; volume, which measures interior space, uses cubic units.

Worked example: a closed 5 cm × 2 cm × 3 cm box has surface area 2(10) + 2(15) + 2(6) = 62 cm².

  1. Find the surface area of a closed 8 cm × 3 cm × 2 cm box.
  2. Find the surface area of a cube with edge length 5 cm.
  3. A 7 cm × 4 cm × 3 cm box has no top. Its base is 7 cm × 4 cm. Find the surface area.
  4. Explain why 6 × 4 × 3 does not give the surface area of the story’s box.
Check your practice

1. 92 cm². 2. 150 cm². 3. 94 cm². 4. That product is the volume, 72 cm³; it measures space rather than the six exterior faces.

Close the case · 7 minutes

Find and justify the closed story box’s surface area. Then explain why a paper wrapper might need more material than this ideal total.

“One hundred eight square centimeters,” Mara said. This time she pointed to all six faces.

The net matched the box’s dimensions and face arrangement. It was supporting evidence, not proof of who had made it. Ada opened the box.

Inside lay an atlas page showing a narrow entrance behind the cabinet. Ada checked it against the building record in her office, then arranged for a maintenance worker to inspect the blocked doorway.

The next morning she returned with a photograph. The room existed. Its shelves held survey notebooks.

Eli unfolded the atlas page. Across its edge were three words: Continue at Stone Bridge.

For the first time, their map led beyond the workshop.

Lessons 1.4–1.5 · Independent checkpoint

Carry the ideas with you.

  1. A 16 cm × 9 cm sheet has one triangular corner removed with perpendicular legs 4 cm and 5 cm. Find the remaining area.
  2. A closed rectangular prism measures 9 cm × 5 cm × 2 cm. Find its surface area by listing all face areas.
  3. An open-top box has base 8 cm × 5 cm and height 4 cm. Find its surface area.
  4. A student says equal surface areas establish equal box dimensions. Test the claim using closed boxes of dimensions 1 × 1 × 5 and 1 × 2 × 3.
  5. Explain one thing the workshop group established through calculation and one thing that required observation or another record.
Solutions — check after working independently

1. 134 cm². 2. Faces: 45, 45, 18, 18, 10, 10; total 146 cm². 3. 40 + 64 + 40 = 144 cm². 4. Both have surface area 22 square units despite different dimensions. 5. Calculations establish model areas; confirmation of the actual room required inspection and records.

Challenge: the same total, a different box

Find a closed rectangular prism with whole-number dimensions different from 6 × 4 × 3 but surface area 108 square units. Explain your search.

One solutionA whole-number solution is 1 × 4 × 10: 2(4 + 10 + 40) = 108.

Next story destination: Stone Bridge. Ratios will help the group interpret the survey notebooks. Further geometry lessons and practice will build on this opening sequence.

Return to the map →