Professional Learning/Number and Place ValueFacilitator Guide
The journey / Chapter 6
Chapter 6 · Grade 7

Sign, Size, and Position

How is distance from zero different from order?

The story unfolds

The station records temperatures above and below zero. A reading of negative 0.8 is farther from zero than negative 0.75, yet it is the lower temperature. The decimal digits describe magnitude; the sign locates the number relative to zero.

The mathematics beneath the story

Revisit signed rational-number order, absolute value, and operations using decimal magnitude. Negative-number position and order begin in Grade 6; Grade 7 deepens the reasoning through operations. This is a connection to place value, not a new place-value system.

A learning breakpoint to notice

Comparing absolute values can be confused with comparing signed numbers. A longer decimal string still need not represent a larger magnitude. Use a common unit and locate the numbers before computing.

See the structure

−10−0.80−0.75−0.80 is farther left, but farther from zero.

Teacher investigation

Compare −0.8 and −0.75. Rename them as −0.80 and −0.75, then explain both order and distance from zero.

Try it before revealing the solution. Name every quantity and unit. Accept several valid representations.

Study a completed solution

−0.80 < −0.75 because −0.80 lies farther left on the number line. Yet |−0.80| = 0.80 > 0.75 = |−0.75|. A temperature increase of 0.15 from −0.80 reaches −0.65.

Compare approaches

A number line shows direction and order; common hundredths make the magnitude comparison precise. Absolute value reports distance, so it removes direction rather than making a claim about which signed number is larger.

Analyze an incorrect response

“−0.8 is greater than −0.75 because 80 hundredths is greater than 75 hundredths.” That compares magnitudes. For negative numbers, the greater magnitude lies farther left.

Identify the first invalid inference. Ask what evidence would help the learner revise it.

Complete the reasoning

−0.6 = −__ hundredths. Comparing it with −0.58 gives −0.6 __ −0.58.

Check after trying

60; <. Both use hundredths, and −60 hundredths lies left of −58 hundredths.

Transfer independently

A temperature changes from −1.25 degrees to 0.4 degrees. Find the increase and explain it as two distances joined at zero.

Compare your reasoning

1.65 degrees: 1.25 to reach zero and another 0.40 above it. Equivalently 0.4 − (−1.25) = 1.65.

Pause and reflect

Which unit must students keep track of? What would an accurate answer conceal? Choose a different context or representation to test whether the idea transfers.

Bring it to your classroom

Grade 7 · Printable student practice and a separate teacher key. Includes an optional “Think Like a Mathematician” extension.

Student worksheet (PDF) ↗ Teacher key (PDF) ↗

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